In an isosceles triangle with vertices labeled A,
B, and C, side AB is twice as long as side AC.
If
the perimeter is 200 meters, how long is side BC?
Solution:
The answer is 80 meters.
AB must be equal to BC.
Therefore, let x = AC; then AB = 2x and BC = 2x.
So, 5x = 200 and x = 40, so 2x = 80.
AC can not equal BC, because the lengths of 50, 50, and 100 meters do NOT form a triangle!
Correctly solved by:
| 1. Rusty Snellgrove | Atlanta, GA |
| 2. Trey Genda | Winchester, VA |
| 3. Clark Nesselrodt | Winchester, VA |
| 4. Andrew Crosby | Winchester, VA |