From the integers 1, 2, 3, 4, 5, 6, 7, 8, and 9,
Can you find six different integers, call them
A, B, C, D, E, and F such that
A x B x C = D x E x F ?
Solutions:
A = 1
B = 8
C = 9
D = 3
E = 4
F = 6
Thus, 1 x 8 x 9 = 72 = 3 x 4 x 6
or
A = 2
B = 3
C = 6
D = 1
E = 4
F = 9
Thus, 2 x 3 x 6 = 36 = 1 x 4 x 9
Correctly solved by:
| 1. Jia Ran | Rome, Italy |
| 2. Josh Grewal | Winchester, VA |
| 3. Richard Mocarski | Winchester, VA |
| 4. Sam Stiebel | Winchester, VA |
| 5. Tom Marino | Winchester, VA |
| 6. Christopher March * | Winchester, VA |
| 7. Chris Moats | Winchester, VA |
| 8. Elizabeth Cotter | Oak Hill, VA |
| 9. Chip Schewikarth | Winchester, VA |
| 10. James O'Kane | Winchester, VA |
| 11. David Pugh | Winchester, VA |
| 12. Kirstine Wynn | Winchester, VA |
| 13. Joe Jenkins | Winchester, VA |
| 14. Court Pifer | Winchester, VA |