Answer to March 2009 Problem
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Each letter of the alphabet stands for a different digit from 0 to 9
throughout this addition problem.
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You may send in your answer in the following form: | ||||||||||||||||||||||||||||||||||||
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Solution to the Problem: E=8 G=4 I=0 N=1 O=2 P=5 R=6 T=3 Y=7 482648 40117 + 621 ------- 523386 |
| 1. K. Sengupta | Calcutta, INDIA |
| 2. Richard K. Johnson | La Jolla, California |