If the largest of x consecutive integers is M, what is the smallest integer?

Solution to the Problem:

The smallest integer would be M - x + 1.

Try some examples to find a pattern:
If the consecutive integers are 6, 7, 8, 9, 10, 11, 12
Then M = 12 (the largest of these integers)
and x = 7 (the number of integers)
The smallest integer would be 6, which is 12 - 7 + 1.

Correctly solved by:

1. Brijesh Dave Mumbai City, Maharashtra, India
2. Colin (Yowie) Bowey Beechworth, Victoria, Australia
3. Veena Mg Bangalore, Karnataka, India
4. Wyatt Jensen Mountain View High School,
Mountain View, Wyoming
5. Tanner Erickson Mountain View High School,
Mountain View, Wyoming
6. Kelly Stubblefield Mobile, Alabama