A lady in England was stumped by her 10 year old daughter's maths homework, so she put the problem out on Twitter:
There are 5 times as may pens in box A than box B.
Tom moves 76 pens from box A to box B.
Both boxes now have the same number of pens.
How many pens are in box A now?
Solution to the Problem:
The answer is 114 pens.
Let A = number of pens in box A
Let B = number of pens in Box B.
A = 5B
A - 76 = B + 76
So, A = B + 152
5B = B + 152
4B = 152
B = 38 This is the original number of pens in Box B.
Then A = 5*38 = 190 This is the original number of pens in Box A.
So, after moving 76 pens, both Box A and Box B contain 114 pens.
Correctly solved by:
| 1. K. Sengupta | Calcutta, West Bengal, India |
| 3. Colin (Yowie) Bowey | Beechworth, Victoria, Australia |
| 3. Ritwik Chaudhuri | Santiniketan, West Bengal, India |
| 4. Dr. Hari Kishan |
D.N. College, Meerut, Uttar Pradesh, India |
| 5. Brijesh Dave | Mumbai City, Maharashtra, India |
| 6. Davit Banana | Istanbul, Turkey |
| 7. Seth Cohen | Concord, New Hampshire |
| 8. Mohamed Sheriff (MEDDORA) | Freetown, Western area, Sierra Leone, West Africa |
| 9. Ivy Joseph | Pune, Maharashtra, India |
| 10. Carolina Romero |
Central High School, Grand Junction, Colorado |
| 11. Colter Tims |
Mountain View High School, Mountain View, Wyoming |
| 12. Ellie Barker |
Mountain View High School, Mountain View, Wyoming |
| 13. Kelly Stubblefield | Mobile, Alabama |