Answer to the Problem of the Week

for the week of April 3, 2000

The Six Integer Problem
From the integers 1, 2, 3, 4, 5, 6, 7, 8, and 9, Can you find six different integers, call them A, B, C, D, E, and F such that
A x B x C = D x E x F ?


Solutions:

A = 1
B = 8
C = 9
D = 3
E = 4
F = 6

Thus, 1 x 8 x 9 = 72 = 3 x 4 x 6

or
A = 2
B = 3
C = 6
D = 1
E = 4
F = 9

Thus, 2 x 3 x 6 = 36 = 1 x 4 x 9


Correctly solved by:

1. Jia Ran Rome, Italy
2. Josh Grewal Winchester, VA
3. Richard Mocarski Winchester, VA
4. Sam Stiebel Winchester, VA
5. Tom Marino Winchester, VA
6. Christopher March * Winchester, VA
7. Chris Moats Winchester, VA
8. Elizabeth Cotter Oak Hill, VA
9. Chip Schewikarth Winchester, VA
10. James O'Kane Winchester, VA
11. David Pugh Winchester, VA
12. Kirstine Wynn Winchester, VA
13. Joe Jenkins Winchester, VA
14. Court Pifer Winchester, VA
* Found both solutions using a computer program he wrote in C++