Answer to October 8, 2001 Problem |
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| The BUDGET Truck Problem |
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A Budget Rental Truck is 12 feet 8 inches tall (from the
road to the top of the Van). The cab of the truck is 8
feet long and the van is 24 feet long (see diagram below).
If the front of the truck is 8 feet from a stoplight suspended
18 feet above the road, how far behind the truck must the driver
of a car be so that he can see the stoplight?
Assume that the eye of the driver is 4 feet above the road.
Solution:
This problem could be solved with geometry using similar triangles or it could be solved with trigonometry. In the diagram below, L represents the light (which is 18 feet above the road), T represents the back of the truck (which is 8 + 8 + 24 = 40 feet from the light and 12 feet 8 inches above the road), and E represents the eye of the driver in the car (which is 4 feet above the road and x feet behind the truck). You are solving for x.
The three triangles in the diagram are similar, so you can set up the following proportion:
Using the first two parts of this proportion, you obtain:
Using the first and last parts of this proportion, you obtain: Solving simultaneously, you obtain y = 30 feet and x = 65 feet.
Using trig, you could solve for the measure of the acute angle
which is common to all three triangles.
Keith Mealy wrote: I think you forgot to add a second part to this problem: If driver A actually stays that far behind the rental truck at a light, how long before driver B (the vehicle immediately behind driver A) honks his horn to move up?
a) (Boston) 0.000007 seconds |
| 1. Keith Mealy | Cincinnati, Ohio |
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