Find the lowest integral values for A, B, C, and D where:

A + B = C
A + D = B
2C = 3D
B > 0



Solution to Problem:

Solving simultaneously, you can get
D = (4/5) B and
D = 4A
Then A = (1/5) B and
C = (6/5) B
Since B > 0,
the smallest number for B would be 5 (to make it an integer).
Then D = 4, A = 1, and C = 6.



Correctly solved by:

1. Devin Grim Winchester, VA
2. Matthew Hurst Winchester, VA
3. Angie Cunsolo Winchester, VA
4. Ginger Anderson Winchester, VA
5. Krista Ramey Winchester, VA
6. Barrett Waybright Winchester, VA
7. Ryan Dutton Winchester, VA
8. John Beavers Winchester, VA