Seven guests at a restaurant came,
The first every day,
The second every other day,
The third every third day,
and so on to
the seventh who came once a week.
When will they all come to dine at the
restaurant on the same day? (What is the smallest number of days?)
Solution to Problem: Answer is 420 days.
The least common multiple of 1, 2, 3, 4, 5, 6, and 7 is 420.
Correctly solved by:
| 1. Devin Grim | Winchester, VA |
| 2. Trey Genda | Winchester, VA |
| 3. John Beavers | Winchester, VA |
| 4. Rachel Rasmussen | Winchester, VA |
| 5. Jason Aikens | Winchester, VA |
| 6. Barrett Waybright | Winchester, VA |