October 2020
Problem of the Month

Smallest Integer
Submitted by Brijesh Dave

If the largest of x consecutive integers is M, what is the smallest integer?

Solution to the Problem:

The smallest integer would be M - x + 1.

Try some examples to find a pattern:

If the consecutive integers are
  6, 7, 8, 9, 10, 11, 12

Then M = 12 (the largest of these integers)

and x = 7 (the number of integers)

The smallest integer would be 6,
which is 12 - 7 + 1.

Correctly solved by:

1. Brijesh Dave	Mumbai City, Maharashtra, India
2. Colin (Yowie) Bowey	Beechworth, Victoria, Australia
3. Veena Mg	Bangalore, Karnataka, India
4. Wyatt Jensen	Mountain View High School, Mountain View, Wyoming
5. Tanner Erickson	Mountain View High School, Mountain View, Wyoming
6. Kelly Stubblefield	Mobile, Alabama

Send any comments or questions to: David Pleacher