ABCD and AEBF are rectangles with AE = 1 and EB = 2.
What is the area of ABCD and what are its dimensions?
Show your work.
Solution to the Problem:
The area of rectangle ABCD is 2 square units.
The dimensions are sqrt(5) by 2 / sqrt(5) or approximately 2.236 by .8944.
Use the Pythagorean Theorem to solve for AB: 12 + 22 = AB2
Now substitute the value of x in the expressions for AD and BC and check if they are equal.
Then multiply AD x AB to get the area of ABCD.
Correctly solved by:
| 1. Ritwik Chaudhuri | Santiniketan, West Bengal, India |
| 2. Veena Mg | Bangalore, Karnataka, India |
| 3. Davit Banana | Istanbul, Turkey |
| 4. Jonathan Punke |
Bremen High School, Midlothian, Illinois |
| 5. Cash Henrie |
Mountain View High School, Mountain view, Wyoming |
| 6. Ivy Joseph | Pune, Maharashtra, India |
| 7. K. M. Thomas | Mumbai, Maharashtra, India |
| 8. Dr. Hari Kishan |
D.N. College, Meerut, Uttar Pradesh, India |
| 9. Indianna Covington |
Mountain View High School, Mountain view, Wyoming |
| 10. Colin (Yowie) Bowey | Beechworth, Victoria, Australia |