December 2022
Problem of the Month

FORTY + FIFTY + ZERO + ZERO = NINETY

Solve the following cryptarithm:

FORTY + FIFTY + ZERO + ZERO = NINETY

Each letter represents a different digit.

The solution is:

69582 + 64682 + 3759 + 3759 = 141782

E = 7
F = 6
I = 4
N = 1
O = 9
R = 5
T = 8
Y = 2
Z = 3

K. Sengupta pointed out that if we allow a leading zero, there is another solution:
34172 + 39372 + 8514 + 8514 = 090572

Correctly solved by:

1. K. Sengupta	Calcutta, India
2. Colin (Yowie) Bowey	Beechworth, Victoria, Australia
3. Davit Banana	Istanbul, Turkey
4. Lillian Morwood	Mountain View High School, Mountain View, Wyoming
5. Brinley Barnes	Mountain View High School, Mountain View, Wyoming
6. Colter Tims	Mountain View High School, Mountain View, Wyoming
7. Jaxson Hadley	Mountain View High School, Mountain View, Wyoming
8. Cody Downey	Mountain View High School, Mountain View, Wyoming
9. Dr. Hari Kishan	D.N. College, Meerut, Uttar Pradesh, India
10. Ritwik Chaudhuri	Santiniketan, West Bengal, India

Send any comments or questions to: David Pleacher