If the smallest of x consecutive integers is M, what is the largest integer?
Solution to the Problem:

Here is the solution:

The largest integer would be M + x - 1.

Try some examples to find a pattern:

If the consecutive integers are
6, 7, 8, 9, 10, 11, 12

Then M = 6 (the smallest of these integers)
and x = 7 (the number of integers)
The largest integer would be 12,
which is 6+7-1.


Correctly solved by:

1. Dr. Hari Kishan D.N. College,
Meerut, Uttar Pradesh, India
2. Colin (Yowie) Bowey Beechworth, Victoria, Australia
3. Davit Banana Istanbul, Turkey
4. Brijesh Dave Mumbai City, Maharashtra, India
5. Kamal Lohia Holy Angel School,
Hisar, Haryana, India
6. Ivy Joseph Pune, Maharashtra, India
7. Gayathri U Palakkad, Kerala, India
8. Kelly Stubblefield Mobile, Alabama, USA